-16x^2+112x+6=130

Solution for -16x^2+112x+6=130 equation:

-16x^2+112x+6=130

We move all terms to the left:

-16x^2+112x+6-(130)=0

We add all the numbers together, and all the variables

-16x^2+112x-124=0

a = -16; b = 112; c = -124;
Δ = b2-4ac
Δ = 1122-4·(-16)·(-124)
Δ = 4608
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{4608}=\sqrt{2304*2}=\sqrt{2304}*\sqrt{2}=48\sqrt{2}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(112)-48\sqrt{2}}{2*-16}=\frac{-112-48\sqrt{2}}{-32}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(112)+48\sqrt{2}}{2*-16}=\frac{-112+48\sqrt{2}}{-32}
$